Two wires of the same length and material have a diameter of wire A twice that of wire B. If the resistance of wire B is R then the resistance of wire A is
Two wires of the same length and material have a diameter of wire A twice that of wire B. If the resistance of wire B is R then the resistance of wire A is R/4.
- the resistance of the wire is given by R = ρ*L/A
- because both wires have the same length and the same material so the value of ρ same for both wires.
- The cross-sectional area of the wire is A = πr2
- first wire: RA = ρ*L/πr2 = ρ*L/4πD2/4 because r = D/2 (put D = 2D because wire A have double diameter)
- second wire: RB = ρ*L/πr2 = ρ*L/πD2/4 because r = D/2
- divide RA and RB i-e RA/RB = 1/4
- RA = RB/4
This question is about MSc Electricity and Magnetism MCQs. This is the previous year’s question about the competitive exams.
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