The resistance of a piece of a wire is 15Ω. It is bent to form an equilateral triangle. What is the equivalent resistance between any two corners of the triangle?

  1. 3.3 Ω
  2. 5 Ω
  3. 10 Ω
  4. 15 Ω


The resistance of a piece of a wire is 15Ω. It is bent to form an equilateral triangle. What is the equivalent resistance between any two corners of the triangle?

The resistance of a piece of a wire is 15Ω. It is bent to form an equilateral triangle. The equivalent resistance between any two corners of the triangle is 3.3 Ω.

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  1. using shortcut
  2. when you have an equilateral triangle means a triangle having equal sides, and you want to find the equivalent resistance between any two corners of the triangle then used this formula
  3. equivalent resistance: Req = 2/3 * r
  4. where r is the resistance of any resistor.
  5. put r = 5 in our case get 2/3 * 5 = 10/3 = 3.3 Ω
  6. using another method to find equivalent resistance
  7. from the figure, any two resistors are in series and equivalent resistance for these two resistors are
  8. Req = 5Ω + 5Ω = 10Ω
  9. this equivalent resistance in parallel with the third resistor
  10. 1/Req = 1/10 + 1/5 = 3/10
  11. hence Req = 10/3 = 3.3Ω

This question is about MSc Electricity and Magnetism MCQs. This is the previous year’s question about the competitive exams.


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