- 3.3 Ω
- 5 Ω
- 10 Ω
- 15 Ω
The resistance of a piece of a wire is 15Ω. It is bent to form an equilateral triangle. What is the equivalent resistance between any two corners of the triangle?
The resistance of a piece of a wire is 15Ω. It is bent to form an equilateral triangle. The equivalent resistance between any two corners of the triangle is 3.3 Ω.
- using shortcut
- when you have an equilateral triangle means a triangle having equal sides, and you want to find the equivalent resistance between any two corners of the triangle then used this formula
- equivalent resistance: Req = 2/3 * r
- where r is the resistance of any resistor.
- put r = 5 in our case get 2/3 * 5 = 10/3 = 3.3 Ω
- using another method to find equivalent resistance
- from the figure, any two resistors are in series and equivalent resistance for these two resistors are
- Req = 5Ω + 5Ω = 10Ω
- this equivalent resistance in parallel with the third resistor
- 1/Req = 1/10 + 1/5 = 3/10
- hence Req = 10/3 = 3.3Ω
This question is about MSc Electricity and Magnetism MCQs. This is the previous year’s question about the competitive exams.
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