A force F = (5, 3, -6) is applied at a point r = (1, 0, -3) m. Calculate the torque due to this force:

  1. 7i – 9j + 3k
  2. -9i + 2j + 3k
  3. 9i – 9j + 3k
  4. 3i – 3j – k


Answer:

The torque due to this force is 9i – 9j + 3k

Helping Concept:

  1. F = (5, 3, -6)
  2. r = (1, 0, -3)
  3. \dpi{80} \fn_jvn \overrightarrow{\tau} = \overrightarrow{r}\times \overrightarrow{F}
  4. \dpi{80} \fn_jvn \overrightarrow{\tau }= \begin{vmatrix} \hat{i} & \hat{j} & \hat{k}\\ 1 & 0 & -3\\ 5 & 3 & -6 \end{vmatrix}
  5. \dpi{80} \fn_jvn \overrightarrow{\tau } = \hat{i}(0+9)-\hat{j}(-6+15)+\hat{k}(3+0)
  6. \dpi{80} \fn_jvn \overrightarrow{\tau } = 9\hat{i} - 9\hat{j} + 3\hat{k}

Related Questions:

 

One Comment to “A force F = (5, 3, -6) is applied at a point r = (1, 0, -3) m. Calculate the torque due to this force:”

  1. Simply dеsіre to say your article іs as astounding. The clеаrness in your post iѕ just excellent
    and i could assume you are an exρert on this subject.
    Well with yоur permission let me to grab your feed
    tⲟ keep updated wіth fօrthcoming poѕt. Thanks a
    million ɑnd please carry on the rewarding work.

Leave a Reply

Your email address will not be published. Required fields are marked *