# A force F = (5, 3, -6) is applied at a point r = (1, 0, -3) m. Calculate the torque due to this force:

1. 7i – 9j + 3k
2. -9i + 2j + 3k
3. 9i – 9j + 3k
4. 3i – 3j – k

The torque due to this force is 9i – 9j + 3k

### Helping Concept:

1. F = (5, 3, -6)
2. r = (1, 0, -3)
3. $\dpi{80}&space;\fn_jvn&space;\overrightarrow{\tau}&space;=&space;\overrightarrow{r}\times&space;\overrightarrow{F}$
4. $\dpi{80}&space;\fn_jvn&space;\overrightarrow{\tau&space;}=&space;\begin{vmatrix}&space;\hat{i}&space;&&space;\hat{j}&space;&&space;\hat{k}\\&space;1&space;&&space;0&space;&&space;-3\\&space;5&space;&&space;3&space;&&space;-6&space;\end{vmatrix}$
5. $\dpi{80}&space;\fn_jvn&space;\overrightarrow{\tau&space;}&space;=&space;\hat{i}(0+9)-\hat{j}(-6+15)+\hat{k}(3+0)$
6. $\dpi{80}&space;\fn_jvn&space;\overrightarrow{\tau&space;}&space;=&space;9\hat{i}&space;-&space;9\hat{j}&space;+&space;3\hat{k}$

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